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16x^2-75x-6.5=0
a = 16; b = -75; c = -6.5;
Δ = b2-4ac
Δ = -752-4·16·(-6.5)
Δ = 6041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{6041}}{2*16}=\frac{75-\sqrt{6041}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{6041}}{2*16}=\frac{75+\sqrt{6041}}{32} $
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